The only possible product (since sodium compounds ionize) is the weak acid H2CO3. H2SO4(aq) + Na2CO3(aq) --> Na2SO4(aq) + H2CO3. Water - H 2 O. Dihydrogen Monoxide Dihydridooxygen [OH2] HOH Hydrogen Hydroxide Dihydrogen Oxide Oxidane Hydrogen Oxide. espero que te sirva Ionic sodium compounds always ionize so it would be 2 Na+ and CO3 (-2). se te desprendera CO2 y se te formara agua (H2O) y en esta se solubilizara la sal de Na2SO4, o sea. Schwefel hat die Oxidationszahl von +6 in Schwefelsäure Wasserstoff hat beide male +1 als Oxidationszahl Und Sauerstoff hat alle vier male -2 als Oxidationszahl As the concentration of H2SO4 … This particular reaction is a gas evolution reaction, which means a certain compound evolutionizes itself into a gas and water, in this case, H2CO3. You'll notice both of these substances completely dissolve, and are thus called strong electrolytes. Molar Mass of CNa2O3 Oxidation State of CNa2O3. ionic equation--H2SO4 is a strong acid, so it breaks apart completely: 2H+ and SO4 (-2). Сoding to search: 2 CuSO4 + 2 Na2CO3 + H2O = Cu2OH2CO3 + 2 Na2SO4 + CO2 Add / Edited: 26.10.2014 / Evaluation of information: 3.7 out of 5 / number of votes: 3 For 0.000100M H2SO4, [H+] = 0.000198M If you are familiar with doing calculations, you can replicate these results. Na2CO3 Disodium Carbonate Washing Soda Natriumkarbonat Carbonic Acid Sodium Salt (1:2) Anhydrous Sodium Carbonate Soda Ash Carbonic Acid, Disodium Salt. Only a handful of compounds undergo this however. Na2CO3 + H2SO4 -----/ CO2 + H2O + Na2SO4. So the ionic equation is: H2SO4 + Na2CO3 = Na2SO4 + CO2 + H2O.